Margin of Error

Statements lke $\pm 3\%$ The smaller the margin of errors, the greater the accuracy of the measurement

$E=z\sqrt{\frac{p(1-p)}{n}}$ $E=z\sqrt{\frac{p(q)}{n}}$ $E=|z_{\frac{a}{2}}(\frac{\sigma }{\sqrt{n}})|$ z-score is based on the confidence interval given. usually 1.960 from 95% p is probability of success Binomial Distribution