Theorem
- Let
- Let be distinct Eigenvalues of
- Then, there exists a basis such that:
[T]{\beta} = \left[\begin{array}{c|c} diag(c{1}I_{d_{1}},\dots,c_{n}I_{d_{n}}) & C\ \hline 0 & D \end{array}\right]
[T]{\beta} = \left[\begin{array}{c|c} diag(c{1}I_{d_{1}},\dots,c_{n}I_{d_{n}}) & C\ \hline 0 & D \end{array}\right]