Theorem Suppose S:U→V is a linear map Suppose T:V→W is a linear map Then, ker(S)⊂ker(TS) Then, Image(TS)⊂Image(T) Proof Proving ker(S)⊂ker(TS) Pick v∈Ker(S) Calculate TS(v)=T(S(v)) by defn of TS =T(0v) as v∈Ker(S) =0w as T is linear Therefore, v∈Ker(TS) as it follows Ker(S)=Ker(TS) Proving Image(TS)⊂Image(T) Pick w∈Image(TS) w=TS(u) by defn of Image =T(S(u)) by defn of TS =T(v) as S(u)=V Therefore, w∈Image(T)S