Theorem
- Suppose S:U→V is a linear map
- Suppose T:V→W is a linear map
- Then, ker(S)⊂ker(TS)
- Then, Image(TS)⊂Image(T)
Proof
Proving ker(S)⊂ker(TS)
- Pick v∈Ker(S)
- Calculate TS(v)=T(S(v))  by defn of TS
- =T(0v) as v∈Ker(S)
- =0w as T is linear
- Therefore, v∈Ker(TS) as it follows Ker(S)=Ker(TS)
Proving Image(TS)⊂Image(T)
- Pick w∈Image(TS)
- w=TS(u) by defn of Image
- =T(S(u)) by defn of TS
- =T(v) as S(u)=V
- Therefore, w∈Image(T)S