⚠ Switch to EXCALIDRAW VIEW in the MORE OPTIONS menu of this document. ⚠
Text Elements
Bear Can Swim at
They reach the
3m/s
East
side of the river.
The river is flowing
2m/s[North]
The river is
40m
wide.
It takes
16s
for the bear to cross it
What angle is the bear swimming?
What angle is the bear swimming?
What angle is the bear swimming?
2m/s[N]
40m
What we know so far:
v
b
w
= 3m/s
v
w
g
= 2m/s[N]
v
b
wx
= 3cosθ
θ
v
b
wy
= 3sinθ
v
w
gx
= 0
2m/s
3m/s
v
w
gy
= 2
d = 40m
40m
θ
3m/s
t = 16s
If it took him 16s to make 40m, and this 40m is a horizontal distance,
v
b
gx
= 40/16 [W]
= 2.5
N
E
S
W
v
b
gx
=
Remember subscript addition
v
b
wx
v
w
gx
2.5
=
- 0
3cosθ
θ = 33.6
Conventions
Starting at when bear is East of river