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tan( 2Π/9 ) = cot( 13Π/18 )
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Draw angles
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This is case B.
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Proof
There is a 90degree disparity between angle
2Π/9
and angle
13Π/18
Angle
is the bigger one of the two
13Π/18
So,
13Π/18
2Π/9
Should equal Π/2
L.S
R.S
13Π/18
2Π/9
Π/2
13Π/18
4Π/18
9Π/18
Π/2
L.S = R.S!!!!!!
cot(Π/2 - 2Π/9) = tan(2Π/9)