Theorem
- If {anβ} is Bounded
- If {anβ} is Monotone
- In particular, it is either:
- Strictly Increasing and Bounded Above
- Strictly Decreasing and Bounded Below
Then, {anβ} Converges
Proof
Proving Strictly Increasing and Bounded Above Case
- Suppose {anβ} is Bounded Above
- Suppose {anβ} is Strictly Increasing
- Then, βcβR s.t βaβ{anβ},aβ€c
- Then, βx1β,x2ββN,x1β<x2ββΉax1ββ<ax2ββ
- We want to show βlβR,βΟ΅>0,βN>0 s.t n>NβΉβ£anββlβ£<Ο΅
- Consider A={anββ£nβN}βR
- Note that a1ββA so A is non-empty
- Note A is bounded above, as we know {anβ} is bounded above
- By the Completeness Axiom, the Supremum of the set A exists
- Choose l=sup(A)
- Then, choose arbitrary Ο΅>0
- Choose NβN s.t lβΟ΅<aNβ by definition of supremum
- Suppose n>N
- Note that lβΟ΅<aNβ<anβ as {anβ} is strictly increasing
- Note by definition that since l=sup(A),βaβA,a<l
- Note anββA by definition
- Then, anββ€l<l+Ο΅
- Then, by transitivity of <, it follows that lβΟ΅<anβ<l+Ο΅
- βΉβΟ΅<anββl<Ο΅
- β£anββlβ£<Ο΅ by β£β
β£ defn
- Thus, we have shown convergence
- β‘
Examples