Example 1
Example 2
check if these values of x result in the argument being positive
Interval Method
x(x+48) > 0 Critical values are 0 and -48
Test | x < -48 | -48 < x < 0 | 0 < x |
---|---|---|---|
x(x+48) | + | - | + |
-50 is OK 2 = OK
log4(2x+6)=3 43=2x+6 64=2x+6 58=2x x=29
log(3x2+48x)=32 102/3=3x2+48x 102=x2+48x x2+48x−100=0 (x+50)(x−2)=0 x=−50Ux=2 check if these values of x result in the argument being positive
x(x+48) > 0 Critical values are 0 and -48
Test | x < -48 | -48 < x < 0 | 0 < x |
---|---|---|---|
x(x+48) | + | - | + |
-50 is OK 2 = OK